Answer:
The net force is 3933.1 N
Explanation:
Centripetal force (F) = mv^2/r
m is the mass of the discus = 1.6 kg
v is the speed of the discus = 52 m/s
r is the radius of the circle = 1.1 m
F = 1.6×52^2/1.1 = 3933.1 N
The force acting on the discus is 3933 N.
In circular motion, a centripetal acceleration acts on the object which keeps the object under circular motion. The equation of force acting on an object under circular motion is as follows:
[tex]F = \frac{mv^{2} }{r}[/tex]
where, m is the mass of the object = 1.6 kg
v is the velocity = 52 m/s
r is the radius of the circular path = 1.1 m
[tex]F=\frac{1.6*52*52}{1.1}[/tex] = 3933 N is the force acting on the discus, moments before the launch.
Learn more about Circular Motion:
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