Answer : The concentration of Sr²⁺ in ppm is, 8.1 ppm
Explanation : Given,
Mass of solute (Sr²⁺) = 8.1 × 10⁻³ g
Mas of solution = 1 kg = 1000 g
Parts per million (ppm) : It is defined as the mass of a solute present in one million (10⁶) parts by the mass of the solution.
Formula used :
[tex]ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6[/tex]
Now put all the given values in this formula, we get
[tex]ppm=\frac{8.1\times 10^{-3}g}{1000g}\times 10^6=8.1ppm[/tex]
Hence, the concentration of Sr²⁺ in ppm is, 8.1 ppm
Considering the definition of ppm, the concentration of Sr²⁺ measured in ppm is 8.1.
Ppm or part per million is the ratio of the concentration of one substance to the concentration of another, as one unit of solute dissolved in one million units of solvent.
In other words, Parts per million (ppm) is a unit of concentration measurement that measures the number of units of substance that there are for every million units of the set.
It is a unit used to measure the presence of elements in small quantities (trace).
Ppm can be calculated by weight as:
[tex]ppm=\frac{weight of substance tested}{weight of solution}10^{6}[/tex]
The units of mass in the numerator and denominator must be the same.
In this case, you know:
Replacing in the definition of ppm:
[tex]ppm=\frac{8.1x10^{-3} g}{1000 g}10^{6}[/tex]
Solving:
ppm=8.1
Finally, the concentration of Sr²⁺ measured in ppm is 8.1.
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