Answer:
a = 10.07m/s^2
Their acceleration in meters per second squared is 10.07m/s^2
Explanation:
Acceleration is the change in velocity per unit time
a = ∆v/t
Given;
∆v = 50.0miles/hour - 0
∆v = 50.0miles/hours × 1609.344 metres/mile × 1/3600 seconds/hour
∆v = 22.352m/s
t = 2.22 s
So,
Acceleration a = ∆v/t = 22.352m/s ÷ 2.22s
a = 10.07m/s^2
Their acceleration in meters per second squared is 10.07m/s^2
10.1m/s²
Using one of the equations of motion as follows;
v = u + at ----------------------(i)
where;
v = final velocity of the body (Cheetahs) = 50.0 miles/hour
u = initial velocity of the body = 0 (since they start running from rest)
a = acceleration/deceleration
t = time taken for the motion = 2.22s
First convert the final velocity (v) from miles/hour to m/s
Remember that;
1 mile = 1609.34m
1 hour = 60 x 60s = 3600s
Therefore;
50miles/hour = [tex]\frac{50miles}{1 hour}[/tex] = [tex]\frac{50*1609.34m}{3600s}[/tex] = 22.35m/s
=> v = 22.35m/s
Substituting the values of v, u and t into equation (i) gives;
=> 22.35 = 0 + a (2.22)
=> 22.35 = 2.22a
=> a = [tex]\frac{22.35}{2.22}[/tex] = 10.07m/[tex]s^{2}[/tex]
=> a = 10.1m/s² (to 1 decimal place)
Therefore the acceleration in m/s² is 10.1
