Answer:
q = 3.356×10^-6C
Explanation:
In a cube of air,the electric field is perpendicular to the top and bottom of the cube,the total reflux = reflux200 + reflux300
But reflux is given by:
Reflux= E×A = E×A cos theta.
Where theta is the angle between the area vector and the electric field.
Total reflux = E300×A cos180 + E200×A cos0
Total reflux = -E300A + E200A
Total reflux =A (E300-E200)
Total reflux is given by Guass's law = Total reflux =q/Eo
q=Eo×total reflux
q= EoA(E200-E300)q= (8.84×10^-12)(100)^2×(100-60)
q=3.356×10^-6C
