Respuesta :
Answer:
The molality is 0.504 molal
Explanation:
Step 1: Data given
Mass of NaCl = 25.00 grams
Molar mass NaCl = 58.44 g/mol
Mass of water = 850.0grams
Step 2: Calculate moles NaCl
Moles NaCl = mass NaCl / molar mass NaCl
Moles NaCl = 25.0 grams / 58.44 g/mol
Moles NaCl = 0.428 moles
Step 3: Calculate molality
Molality = moles NaCl / mass H2O
Molality = 0.428 moles / 0.850 kg
Molality = 0.504 molal
The molality is 0.504 molal
Answer:
0.50m
Explanation:
Data provided in the question:
Mass of the sodium chloride (NaCl) = 25.00 g
Mass of water in the solution = 850.0 g
Now,
We know molality
= Amount of substance (in mol) of solute ] ÷ [ mass (in kg) of the solvent ]
also,
Molar mass of NaCl = 58.44 g/mol
Thus,
Moles of NaCl = 25g ÷ (58.44 g/mol)
= 0.428 mol
Solvent = 850.0 g = 0.85Kg
Thus,
Molality = 0.428 mol ÷ 0.85Kg
= 0.50m
