Answer:
The volume of 6.0 M HCl(aq) solution required = 41.67 mL
Explanation:
Considering
[tex]Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}[/tex]
Given that:
[tex]Molarity_{working\ solution}=20\ mM=1.0\ M[/tex]
[tex]Volume_{working\ solution}=250\ mL[/tex]
[tex]Volume_{stock\ solution}=?[/tex]
[tex]Molarity_{stock\ solution}=6.0\ M[/tex]
So,
[tex]1.0\ M\times 250\ mL=6.0\ M\times Volume_{stock\ solution}[/tex]
[tex]Volume_{stock\ solution}=\frac{1.0\times 250}{6.0}\ mL=41.67\ mL[/tex]
The volume of 6.0 M HCl(aq) solution required = 41.67 mL