Answer:
The sum of the coefficients is 9
MnO2 + 4HCl → Cl2 + MnCl2 + 2H2O
Explanation:
Step 1: The unbalanced equation
MnO2 + HCl → Cl2 + MnCl2 + H2O
Step 2: Balancing the equation
MnO2 + HCl → Cl2 + MnCl2 + H2O
On the left side we have 1x Cl (in HCl), on the right side we have 4x Cl (2x in Cl2 and 2x in MnCl2). To balance the amount of Cl on both sides, we have to multiply HCl, on the left side, by 4.
MnO2 + 4HCl → Cl2 + MnCl2 + H2O
On the left side we have 4x H (in 4HCl), on the right side we have 2x H (in H2O). To balance the amount of H on both sides, we have to multiply H2O, on the right side) by 2. Now the equation is balanced
MnO2 + 4HCl → Cl2 + MnCl2 + 2H2O
The sum of the coefficients is 1 + 4 + 1 + 1 + 2 = 9
