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Consider the solubilities of a particular solute at two different temperatures.
Temperature (°C) Solubility (g/100 gH2O)
20.0 44.0
30.0 80.9
1. Suppose a saturated solution of this solute was made using 60.0 gH 2 O at 20.0°C. How much more solute can be added if the temperature is increased to 30.0°C?

Respuesta :

maacastrobr

Answer:

We can still add 22.2 g of the solute

Explanation:

A saturated solution means that there is as much solute in the solution as its solubility allows.

First we calculate the mass of the solute present in a saturated solution with 60.0 g H₂O at 20.0°C:

  • 60.0 gH₂O * 44 gSolute/100 gH₂O = 26.4 g solute

The ratio of the solubilities at 20 °C and 30 °C is

  • 80.9/44.0 = 1.84

This means that there can be 1.84 times more solute when the temperature is 30 °C.

  • 26.4 g solute * 1.84 = 48.6 g

So the mass of the solute that we can still add is:

  • 48.6 - 26.4 = 22.2 g

mickymike92

22.2 g of the solute can be added to the saturated solution if the temperature is increased to 30.0°C.

What is saturated solution?

A saturated solution is a solution which contains as much solute in the solution as it can hold at that particular temperature.

Solubility increases with temperature.

To determine the mass of more solute if temperatures is increased, the mass of the solute present in a saturated solution with 60.0 g H₂O at 20.0°C is first determined:

60.0 gH₂O * 44 gSolute/100 gH₂O = 26.4 g solute

The ratio of the solubilities at 20 °C and 30 °C is

80.9/44.0 = 1.84

Therefore, there can be 1.84 times more solute when the temperature is 30 °C.

Mass of solute at 30°C is calculated as follows:

26.4 g solute * 1.84 = 48.6 g

Therefore, the mass of the solute that can still be added = 48.6 - 26.4

Mass of additional solute = 22.2 g

Learn more about saturated solutions at: https://brainly.com/question/25496482

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