A particle moves so that its position as a function of time in SI units is r = i + (3.0) t2 j + t k. Write expressions for its velocity and its acceleration as functions of time. Evaluate for t = 5.1 s. i-component of velocity?

Respuesta :

Answer:

i - component of V is zero for any value of t  i-e  no motion in this direction

Explanation:

Since

r= i+3[tex]t^{2}[/tex]j+t k

==> V = [tex]\frac{d r}{dt}[/tex]=[tex]\frac{d(i+3t^{2}j+kt) }{dt}[/tex]

=[tex]6tj+k[/tex]

and acceleration is given by taking derivative of velocity w.r.t  t

==> a= [tex]\frac{dV}{dt}[/tex]=[tex]\frac{d(6tj+k)}{dt}[/tex]=[tex]6j[/tex]

so, V=0i+6tj+k

and

a = 0i+6j+k

i - component of V is zero for any value of t  i-e  no motion in this direction