Respuesta :
Answer:
1.016 seconds
Explanation:
Let's bring out the parameters we were given in the question;
Rate constant k = 0.710 s^-1
Initial Concentration [A] = 0.820 M
Final concentration [A]o = 0.290 M
Time t = ?
Formular relating these parameters is given as;
ln[A] = ln[A]o − kt
Making t subject of interest, we have;
ln[A] - ln[A]o = -kt
kt = ln[A]o - ln[A]
t = (ln[A]o - ln[A]) / k
Substituting the values, we have;
t = ( ln(0.820) - ln(0.290) ) / 0.710
t = 0.7217 / 0.710
t = 1.016 seconds
It would take 1.016 seconds for the concentration of A to decrease from 0.820 M to 0.290 M.
Given:
Rate constant, k = [tex]0.710 s^{-1}[/tex]
Initial Concentration [A] = 0.820 M
Final concentration [A]0 = 0.290 M
Time t = ?
Calculation of "t" using Arrhenius equation:
[tex]ln[A] = ln[A]_0 - kt\\\\ln[A] - ln[A]_0 = -kt\\\\kt = ln[A]_0 - ln[A]\\\\t = (ln[A]_0 - ln[A]) / k[/tex]
On Substituting the values:
[tex]t = ( ln(0.820) - ln(0.290) ) / 0.710\\\\t = 0.7217 / 0.710\\\\t = 1.016 seconds[/tex]
Thus, it would take 1.016 seconds for the concentration of A to decrease from 0.820 M to 0.290 M.
Find more information about Arrhenius equation here:
brainly.com/question/24749252
