Answer : The moles of [tex]Na_3C_6H_5O_7[/tex] produced can be, 0.0123 mole
Explanation : Given,
Moles of [tex]NaHCO_3[/tex] = 0.0370 mol
The given balanced chemical reaction is:
[tex]3NaHCO_3(aq)+H_3C_6H_5O_7(aq)\rightarrow 3CO_2(g)+3H_2O(l)+Na_3C_6H_5O_7(aq)[/tex]
From the balanced chemical reaction we conclude that,
As, 3 moles of [tex]NaHCO_3[/tex] react to give 1 mole of [tex]Na_3C_6H_5O_7[/tex]
So, 0.0370 moles of [tex]NaHCO_3[/tex] react to give [tex]\frac{0.0370}{3}\times 1=0.0123mole[/tex] of [tex]Na_3C_6H_5O_7[/tex]
Thus, the moles of [tex]Na_3C_6H_5O_7[/tex] produced can be, 0.0123 mole