Respuesta :
Answer:
9 times
Explanation:
A + 2B → products
rate = k[A][B]2
While holding the concentration of A constant, the concentration of B is tripled. Predict by what factor the rate of reaction increases.
We can achieve this by given the concentration dummy values.
Assuming the following values (Any number works, or letters);
concentration of A = 1
Concentration of B = 2
rate = k[A][B]2
rate = k (1)* (2)^2
rate = k 4 ....... i
When Conc of B is tripled;
Concentration of B = 3 * 2 = 6
rate = k[A][B]2
rate = k (1) * (6)^2
rate = k 36 .... ii
Comparing both rates;
The ratio is 36: 4, upon simplifying = 9 : 1
This means the factor increases by 9 times
The speed at which a chemical reaction occurs to yield products is called the rate of reaction. The reaction rate will increase by nine times.
What is the rate of reaction?
The rate of the reaction depends on the concentration and depicts the rate of the change of the reactants into products during the chemical changes.
The reaction is shown as,
[tex]\rm A + 2B \rightarrow products[/tex]
The rate of reaction is shown as,
[tex]\rm rate = k[A][B]^{2}[/tex]
The concentration of A is constant and of B is tripled. Let the concentration be,
- Concentration of A = 1
- Concentration of B = 2
So, the rate of reaction will be,
[tex]\begin{aligned}\rm rate &= \rm k[A][B]^{2}\\\\&= \rm k (1)\times (2)^{2}\\\\&= \rm k\; 4 \end{aligned}\end{aligned}[/tex]
When the concentration of the B is tripled then, the concentration of B = 6
Now the rate of reaction will be,
[tex]\begin{aligned}\rm rate &= \rm k[A][B]^{2}\\\\&= \rm k (1)\times (6)^{2}\\\\&= \rm k \;36 \end{aligned}\end{aligned}[/tex]
Comparing the rate of the reactions we get, the ratio of 9:1.
Therefore, the factor increases by nine times.
Learn more about the rate of reaction here:
https://brainly.com/question/14978272
