Respuesta :
First mug holds the most
Solution:
Given that,
You are choosing between two mugs
The volume of cylinder is given as:
[tex]V = \pi r^2h[/tex]
Where,
r is the radius and h is the height
One has a base that is 5.5 inches in diameter and a height of 3 inches
[tex]radius = \frac{diameter}{2}[/tex]
Therefore,
[tex]r = \frac{5.5}{2}\\\\r = 2.75[/tex]
Also, h = 3 inches
Thus volume of cylinder is given as:
[tex]V = \pi \times 2.75^2 \times 3\\\\V = 3.14 \times 22.6875\\\\V = 71.23875 \approx 71.24[/tex]
Thus first mug holds 71.24 cubic inches
The other has a base of 4.5 inches in diameter and a height of 4 inches
[tex]Radius = \frac{4.5}{2}\\\\r = 2.25[/tex]
h = 4 inches
Therefore,
[tex]V = 3.14 \times 2.25^2 \times 4\\\\V = 3.14 \times 20.25\\\\V = 63.585[/tex]
Thus the second mug holds 63.585 cubic inches
On comparing, volume of both mugs,
Volume of first mug > volume of second mug
First mug holds the most
