Respuesta :

Answer:

SORRY IDK BUT THX

Explanation:

leena

Hi there!

The angular velocity is equivalent to:

[tex]\omega(t) = \theta'(t) = \frac{d\theta}{dt}[/tex]

Take the derivative using the power rule:

[tex]w(t) = \frac{d\theta}{dt} = \boxed{6t + 2}[/tex]

The angular acceleration is equivalent to:

[tex]\alpha(t) = \frac{d\omega}{dt}[/tex]

Differentiate once again:

[tex]\boxed{\alpha(t) = 6}[/tex]