Answer:
The maximum range obtainable by a person if he has a take-off speed of 9.5 m/s is 9.21 m
Explanation:
The only assumptions are that
Acceleration due to gravity = 9.8 m/s²
The equation for range of a projectile, R = (u² sin 2θ)/g
u = initial takeoff velocity = 9.5 m/s, θ = angle of jump.
To attain the maximum range, the (sin 2θ) has to be maximized to 1, that is,
Sin 2θ = 1 = sin 90°
2θ = 90°
θ = 45°
Therefore, the maximum angle of jump had to be 45°
R = (9.5² sin (2×45°))/9.8 = 9.5²/9.8 = 9.21 m
