Answer:
(A) Tangential speed will be equal to 7.09 m/sec
(B) Radial acceleration will be equal to [tex]128.5629rad/sec^2[/tex]
Explanation:
We have given angular speed of the wheel [tex]\omega =2.89rev/sec=2.89\times \frac{2\pi rad}{sec}=18.149rad/sec[/tex]
Radius of the track r = 39.1 cm = 0.391 m
(A) Tangential speed will be equal to [tex]v=\omega r[/tex], here [tex]\omega[/tex] is angular speed and r is radius
So tangential speed [tex]v=18.149\times 0.391=7.09m/sec[/tex]
So tangential speed will be equal to 7.09 m/sec
(B) Radial acceleration will be equal to [tex]a=\frac{v^2}{r}=\frac{7.09^2}{0.391}=128.5629rad/sec^2[/tex]
So radial acceleration will be equal to [tex]128.5629rad/sec^2[/tex]