Respuesta :
Answer:
[tex] I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A[/tex]
Explanation:
For this case we have the following info given:
Number of Na+ ions [tex] 5.7 x10^{11} ions[/tex]
Each ion have a charge of +e and the crage of the electron is [tex] 1.6 x10^{-19}C[/tex]
The time is given [tex] t = 7 ms[/tex] if we convert this into seconds we got:
[tex] t = 7ms * \frac{1s}{1000 ms}= 0.007s[/tex]
Now we can use the following formula given from the current passing thourhg a meter of nerve axon given by:
[tex] Q = Ne[/tex]
Where N represent the number of ions, e the charge of the electron and Q the total charge
If we replace on this case we have this:
[tex] Q= 5.7x10^{11} * (1.6 x10^{-19}C) = 9.12x10^{-8} C[/tex]
And from the general definition of current we know that:
[tex] I =\frac{Q}{t}[/tex]
And since we know the total charge Q and the time we can replace:
[tex] I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A[/tex]
The current during the inflow charge in the meter axon for this case is [tex] 13.02 \mu A[/tex]
