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A galvanometer has full scale deflection current of 500 micro-Ampere, and resistance of 100 Ohm. Shunt with what resistance has to be combined with the galvanometer in order to transform it to an ammeter able to measure current of 10 Ampere full scale?

Respuesta :

Answer:

resistance of shunt required = 5 ohms

Explanation:

A shunt is a low resistance that is connected in parallel to a galvanometer in order to convert it to a voltmeter.

since the shunt and galvanometer are connected in parallel, then voltage across the galvanometer is equal to voltage across the shunt.

[tex]V_{s} = V_{g}\\ V=IR\\I_{s}R_{s}=I_{gR_{g} }[/tex]

[tex]R_{s}=\frac{I_{g}R_{g} }{I_{s} }[/tex]

[tex]R_{s}= \frac{500*10^{-3}*100 }{10}[/tex]

[tex]R_{s}=[/tex]5Ω