The emf is doubled
Explanation:
The work done by a battery to move a unit charge through the battery from one terminal to the other is equal to the change in electric potential energy of the charge, therefore it can be written as
[tex]W=q\Delta V[/tex]
where
q is the charge
[tex]\Delta V[/tex] is the potential difference through which the charge has been moved
Since the charge is moving through the battery, this means that the potential difference is equal to the emf of the battery [tex]\epsilon[/tex], therefore
[tex]W=q\epsilon[/tex] (1)
In this problem, we are told that the work done by the battery is doubled, so
[tex]W'=2W[/tex]
From eq.(1), we see that the emf of the battery is proportional to the work done: therefore, since the work doubles, the battery's emf doubles as well.
Learn more about potential difference:
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