Answer:
n+1; n+1; n-1; n-1
Explanation:
Separation of homologous chromosomes during anaphase I result in a reduction of the chromosome number to half in the daughter cells of meiosis. If two homologous chromosomes of a pair fail to separate from each other, they both will move to the same pole. In this case, one daughter cell of meiosis I will have both the homologous chromosomes of a pair (n+1) while the other one will lack it (n-1). Meiosis II in these two daughter cells will form a total of four cells. Two of the daughter cells will have one extra chromosome (n+1) while the rest two will lack one chromosome from the haploid set (n-1).
