Answer:
v(6) = 62
At any given time: v(t) = 10t + 2
Step-by-step explanation:
The equation that describes the position of the object is:
[tex]s(t) =5t^2+2t+2[/tex]
The instantaneous velocity at any given time, v(t), is the derivate of the position expression:
[tex]\frac{ds(t)}{dt}=v(t) =10t+2[/tex]
For t = 6, the instantaneous velocity is:
[tex]v(6) =10*6+2\\v(6) = 62[/tex]
The instantaneous velocity when t=6 is v(6) = 62 units of distance/units of time.
