The standard free energy of activation of one reaction A is 95.00 kJ mol–1 (22.71 kcal mol–1). The standard free energy of activation of another reaction B is 74.20 kJ mol–1 (17.73 kcal mol–1). Assume a temperature of 298 K and 1 M concentration.
By what factor is one reaction faster than the other?
Which reaction is faster?
(a) Reaction A is faster.
(b) Reaction B is faster.
(c) Cannot be determined.

Respuesta :

Answer:

The answer to the questions are as follows

Reaction B is 4426.28 times faster than reaction A

(b) Reaction B is faster.

Explanation:

To solve the question we are meant to compare both reactions to see which one is faster

The values of the given activation energies are as follows

For A

Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and

for  B

Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

The Arrhenius Law is given by

k = [tex]Ae^{\frac{-E_{a} }{RT} }[/tex]

Where

k = rate constant

Ea = activation energy

R = universal gas constant

T = temperature  (Kelvin )

A = Arrhenius factor

Therefore

For reaction A, the rate constant k₁ is given by k₁ = [tex]Ae^{\frac{-95000}{(8.314)(298)} }[/tex]

And for B the rate constant k₂ is given by k₂ = [tex]Ae^{\frac{-74200 }{(8.314)(298)} }[/tex]

k₁ = A×2.225×10⁻¹⁷

k₂ = A×9.850×10⁻¹⁴

As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times

(b) Reaction B is faster by a factor of 4426.28 times.

The values of the given activation energies are as follows

For A:

Ea = [tex]95.00 kJ mol^{-1} (22.71 kcal mol^{-1})[/tex]

For B:

Ea = [tex]74.20 kJ mol^{-1} (17.73 kcal mol^{-1})[/tex]

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

According to Arrhenius Law:

[tex]k=Ae^{\frac{-E_a}{RT}[/tex]

where

k = rate constant

Ea = activation energy

R = universal gas constant

T = temperature  (Kelvin )

A = Arrhenius factor

Thus,

For reaction A, the rate constant k₁ is given by:

[tex]k_1=Ae^{\frac{-95000}{RT}[/tex]

For reaction B, the rate constant k₂ is given by:

[tex]k_2=Ae^\frac{-74200}{RT}[/tex]

The rate constants for the respective reactions are :

[tex]k_1 = A*2.225*10^{-17}\\k_2 = A*9.850*10^{-14}[/tex]

As seen from the above Reaction B is faster than reaction A by [tex]\frac{(A*9.850*10^{-14})}{(A*2.225*10^{-17}) }=4426.28[/tex] times

Thus, correct option is b.

Find more information about Arrhenius Law here:

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