Answer:
The sample mean is 127.33 kN and sample standard deviation is 26.59 kN.
Step-by-step explanation:
We are given the following in the question:
97, 97, 102, 102, 102, 103, 103, 108, 127, 127, 129, 129, 141, 159, 164, 164, 164, 174
Formula:
[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}[/tex]
where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Mean =\displaystyle\frac{2292}{18} = 127.33[/tex]
Sum of squares of differences = 12730
[tex]s = \sqrt{\frac{12730}{17}} = 26.59[/tex]
Thus, the sample mean is 127.33 kN and sample standard deviation is 26.59 kN.