Answer:
- [tex]a^n\left(1+a\right)[/tex]
Step-by-step explanation:
Considering the expression
[tex]a^n+a^{\left(n+1\right)}[/tex]
Steps
[tex]a^n+a^{n+1}[/tex]
[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c[/tex]
[tex]a^n+a^1a^n[/tex]
[tex]\mathrm{Factor\:out\:common\:term\:}a^n[/tex]
[tex]a^n\left(1+a\right)[/tex]
Therefore, factoring [tex]a^n+a^{\left(n+1\right)}[/tex] will bring [tex]a^n\left(1+a\right)[/tex].
Keywords: factor, expression
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