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A charge of 9 pC is uniformly distributed throughout the volumebetween concentric spherical surfaces having radii of 1.6 cmand
3.6 cm. Let: ke =8.98755×109 N·m2/C2. What is themagnitude of the electric field
2.3 cm from the center of the surfaces? Answer in units of N/C

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mshahzaib247

Answer:

Electric Field = 3.369 x 10^4 N/C

Explanation:

Radius = r = (r1 + r2) / 2 = (1.6 + 3.6) /2 = 2.6 cm + 2.3 cm = 4.9 cm = 0.049 m

As we know, Electric field = E = kQ/r.r

= 8.98755 x 10^9 x 9 x 10^-9 / 0.049 x 0.049 = 33689.275 N/C

= 3.369 x 10^4 N/C

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