The population will be 1 million after 20.8 years (2028)
Step-by-step explanation:
The population at time can be described by the following equation:
[tex]p(n)=p_0 (1+\frac{1.47}{100})^n[/tex]
where
p(n) is the population n years after year 2000
[tex]p_0 = 738,000[/tex] is the initial population at year 2000
n is the number of years after year 2000
1.47% is the rate of growth of the population
Here we want to find the year n after which the population is 1 million:
[tex]p(n)=1,000,000[/tex]
Substituting and solving the equation for n, we find:
[tex](1+\frac{1.47}{100})^n = \frac{p(n)}{p_0}\\(1.0147)^n = \frac{p(n)}{p_0}\\n=log_{1.0147}(\frac{p(n)}{p_0})=log_{1.0147}(\frac{1,000,000}{738,000})=20.8 y[/tex]
So, after 20.8 years.
Learn more about population growth:
brainly.com/question/10689103
#LearnwithBrainly
