Answer : The concentration of [tex]CO_2[/tex] is, 0.12 M
Explanation :
Using Henry's law :
[tex]C_{CO_2}=k_H\times p_{CO_2}[/tex]
where,
[tex]C_{CO_2}[/tex] = concentration of [tex]CO_2[/tex] = ?
[tex]p_{CO_2}[/tex] = partial pressure of [tex]CO_2[/tex] = 4.5 atm
[tex]k_H[/tex] = Henry's law constant = [tex]3.1\times 10^{-2}mol/L.atm[/tex]
Now put all the given values in the above formula, we get:
[tex]C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)[/tex]
[tex]C_{CO_2}=0.1395M\approx 0.12M[/tex]
Thus, the concentration of [tex]CO_2[/tex] is, 0.12 M