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Steam at a temperature TH = 205 ∘C and p = 1.00 atm enters a heat engine at an unknown flow rate. After passing through the heat engine, it is released at a temperature TC = 100 ∘C and p = 1.00 atm . The measured power output P of the engine is 300 J/s , and the exiting steam has a heat transfer rate of HC = 2400 J/s . Find the efficiency e of the engine and the molar flow rate n/t of steam through the engine. The constant pressure molar heat capacity Cp for steam is37.47 J/(mol⋅K) .

Part A:
What is the efficiency of the heat engine?
Express the efficiency numerically to three significant figures.

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Answer:

0.11

Explanation:

Power output = 300 J/s

Power of exiting steam = 2400 J/s

Balancing the power

Power Input = Power output + Power of exiting steam

[tex]\text{Power I/P}=300+2400=2700\ J/s[/tex]

Efficiency is given by

[tex]\eta=\dfrac{\text{Power O/P}}{\text{Power I/P}}\\\Rightarrow \eta=\dfrac{300}{2700}\\\Rightarrow \eta=0.11[/tex]

The efficiency is 0.11

The efficiency of the heat engine is 0.11.

  • The calculation is as follows;

The Efficiency of the engine e is

[tex]=\frac{ Power\ O/P}{Power \ I/P} \\\\= \frac{300}{2400 + 300} \\\\= \frac{300}{2700}[/tex]

e = 300 / 2400 + 300

= 300 / 2700

= 0.1111

Or e = 11.11 %

Learn more: brainly.com/question/16911495