Answer:
The value of the acceleration of gravity of the Unknown Planet = 1.14 [tex]\frac{m}{s^{2} }[/tex]
Explanation:
length of the pendulum (L)= 1.15 m
Time period (T)= 6.29 seconds
We know that time period of a simple pendulum is given by
⇒ T = 2[tex]\pi[/tex] × [tex]\sqrt\frac{L}{g}[/tex]
put the values in the above formula we get
⇒ T = 2[tex]\pi[/tex] × [tex]\sqrt \frac{1.15}{g}[/tex]
⇒ 6.29 = 2[tex]\pi[/tex] × [tex]\sqrt \frac{1.15}{g}[/tex]
By solving the above equation we get
⇒ g = 1.14 [tex]\frac{m}{s^{2} }[/tex]
This is the value of the acceleration of gravity of the Unknown Planet.
