Answer:
0.999 N.
Explanation:
From the question,
The formula for the force on a conductor carrying current in a magnetic field is given as,
F = BILsinФ..................... Equation 1
Where F = force on the wire, B = magnetic field, I = current carried by the wire, L = length of the wire, Ф = angle between the wire and the magnetic field.
Given: B = 0.37 T, I = 2.3 A, L = 2 m, Ф = 30°
Substitute into equation 1
F = 0.37(2.3)(2)(sin30)
F = 0.37(2.7)(2)(0.5)
F = 0.999 N.
Hence the force on the wire = 0.999 N.
