Answer:
[tex]V=1.77m/s[/tex]
Explanation:
#Using the conservation of momentum , momentum before equals momentum after([tex]p=mv)[/tex].
-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.
Hence:
[tex]9.0\times 5.2+17.4\times 0=(9+17.4)V\\\\V=\frac{9\times5.2}{9+17.4}\\\\=1.77m/s\\[/tex]
Hence, the final velocity of the cart and bag is 1.77m/s
