Answer:
the thickness of the mica is 6.64μm
Explanation:
By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation
[tex]\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))[/tex]
Where
L = Thickness
n = Index of refraction of each material
[tex]\lambda = Wavelength[/tex]
Our values are given as
[tex]\Phi = 7(2\pi)L=tn_1 = 1.58n_2 = 1\lambda = 550nm[/tex]
Replacing our values at the previous equation we have
[tex]\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))[/tex]
[tex]t = \frac{7*550}{1.58-1}\\t = 6637.931nm \approx 6.64\mu m[/tex]
the thickness of the mica is 6.64μm
