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A student wants to make a very small particle accelerator using a 9 V battery. What speed will a proton have after being accelerated from rest through the 9 V potential difference? What speed will an electron have after being accelerated from rest through the 9 V potential difference?

Respuesta :

Answer:

v = 4.15 10⁴ m / s

Explanation:

Suppose that all the energy in the battery is converted into kinetic energy of the proton

            U = K

           q V = ½ m v²

            v = √ 2q V/m

            v = √ (2  1.6 10⁻¹⁹ /1.67 10⁻²⁷  9)

            v = √( 17.2455 10⁸)

            v = 4.15 10⁴ m / s

Relativistic corrections are not needed as this speed is much less than the speed of light

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