A bomb falls with velocity v(t)=C(1−e−kt), where C and k are constants. What is the terminal velocity of the bomb? That is, what is the maximum valocity the bomb can reach regardless of the height of the bomber?

Respuesta :

Answer:

The terminal velocity is equal to C.

Explanation:

Making the assumption that k and t are positive, we then have that -kt is negative. The value of e^(-kt) will be equal to 1/(e^(kt))

If t increases, e^(kt) will increase exponentially and its reciprocal 1/(e^(kt)) will approach zero.

So, we have:

v(t) = C*(1-0)

v(t) = C*(1)

v(t) = C

Therefore, C is the terminal velocity.

The maximum valocity the bomb can reach regardless of the height of the bomber is;

v_max = C

We are given;

v(t) = C(1 - e^(-kt))

Now, when dealing with exponential questions, the exponential function usually approaches 0 the more negative the exponent becomes.

Now, we are told to find the maximum velocity as the regardless of the height.

Since the exponent of the exponential function is negative, it implies that as the time is increasing to when the velocity is maximum, the exponential function e^(-kt) will approach zero.

Thus, if e^(-kt) will approach zero, then we have;

v_max = C(1 - 0)

v_max = C

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