Answer:
805 kg/m^3.
Explanation:
Okay, in the question above we are given the following parameters; the mass of steel gasoline= 2.50-kg, volume of gasoline it can hold= 20.0 L. Then we are asked to calculate the average density of the full can.
Recall that the formula for Calculating density = mass/ volume.
So, the total mass of the full can= mass of the steel can, m1 + mass of the gasoline, m2.
Although, we are not given but the density of gasoline = 0.68 g/cm^3 or 6.7 × 10^2 kg/m^3. (Note that you can use any of the value for density of gasoline just take note of the units, for instance one is in g/cm^3 and the other is in kg/m^3). For instance, if we take the one in g/cm^3 we have;
The mass of gasoline = 0.68 × (10^3 × 20).
Mass of gasoline = 13.6 ×10^3 g or 13.6 kg.
Since the mass in the question is given to us In kilograms we will be using the kg unit.
Therefore, the total mass of the full can= mass of the steel can, m1 + mass of the gasoline, m2.
===>2.50 + 13.6.
Then, going back to the formula for Calculating density, we have;
Average density= 2.50 + 13.6/ 20 × 10^3.
Average density = 805 kg/m^3.
