Answer:
Explanation:
Given ; P1 = 100 kPa, T1 = 30°C, T2 = 90°C, P2 = 200 kPa, V1 = 350 m/s
From energy conservation at inlet and outlet
h1 + (1/2)v1² = h2 + (1/2)v2²
CpT1 + (1/2)v1² = CpT2 + (1/2)v2²
.718(90-30) x 103= 0.5x (350²-v2²)
velocity at the exit of a diffuser ; V2=190.63m/s