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If the electric field in an EM wave in free space has a peak magnitude of 8.1×10−5V/m, what is the peak magnitude of the magnetic field strength? Express your answer using two significant figures.

Respuesta :

Answer:

2.7 * 10⁻¹³ T

Explanation:

The electromagnetic wave is produced when an oscillating electric and magnetic field interacts each other perpendicularly.

In an electromagnetic wave, the electric field peak magnitude E and the magnetic field peak magnitude B are related by

[tex]E = cB[/tex]

where ,

c = 3 * 10⁸m/s

E = 8.1×10−5V/m

the peak magnitude of the magnetic field:

[tex]B = \frac{E}{C} \\B = \frac{8.1 \times 10^-^5 }{3 \times 10^8 } \\= 2.7 \times 10^-^1^3[/tex]

2.7 * 10⁻¹³ T