Answer:
The value of heat transfer to the room = 9.145 J
Explanation:
Temperature of the room ([tex]T_{H}[/tex]) = 30.8 degree = 303.8 kelvin
Temperature of the Surrounding ([tex]T_{L}[/tex]) = - 2.42 degree = 270.58 kelvin
Electrical energy consumed (W) = 1 J
Heat transfer to the room is given by the formula [tex]\frac{Q_{H} }{W}[/tex] = [tex]\frac{T_{H} }{T_{H} - T_{L} }[/tex]
⇒ [tex]Q_{H}[/tex] = [tex]\frac{T_{H} }{T_{H} - T_{L} }[/tex] × W
Put all the values in the above formula we get
⇒ [tex]Q_{H}[/tex] = [tex]\frac{303.8}{303.8 - 270.58}[/tex] × 1
⇒ [tex]Q_{H}[/tex] = 9.145 J
This is the value of heat transfer to the room.
