Respuesta :
Answer:
243.43 m/s
Explanation:
Hello,I can help you with this.
the kinetic energy is asociated to the mass and the speed of an object,and it is given by:
[tex]E_{k}=\frac{1}{2}mv^{2}[/tex]
where:
[tex]E_{k}[/tex] is the kinetic energy
m is the mass of the object
v is the speed of the object
Step 1
let
bowling ball =mass1=7.13 kg
Speed(1)=4.14 m/s
Ping-Pong ball
mass2=2.34 g
it is given in grams so we have to convert into Kg (dividing by 1000,1kg=1000 g)
[tex]2.34g(\frac{1kg}{1000g} )=0.00234kg[/tex]
so, mass2=0.00234kg
Step 2
according to the problem both have equal Kinetic energy
[tex]E_{1}=\frac{1}{2}m_{1} v_{1} ^{2}\\E_{2}=\frac{1}{2}m_{2} v_{2} ^{2}\\\frac{1}{2}m_{1} v_{1} ^{2}=\frac{1}{2}m_{2} v_{2} ^{2}\\isolate\ v_{2} \\m_{1} v_{1} ^{2}=m_{2} v_{2} ^{2}\\\frac{m_{1} v_{1} ^{2}}{m_{2}}=v_{2} ^{2} \\v_{2}=\sqrt{\frac{m_{1} v_{1} ^{2}}{m_{2}}}\\v_{2}=\sqrt{\frac{7.13kg*(4.41\frac{m}{s}) ^{2}}{0.00234kg}} \\\\v_{2}=\sqrt{59258.526\frac{m^{2} }{s^{2} } } \\\\\\v_{2}=243.43 m/s[/tex]
so the speed of the ping-pong ball should be 243.43 m/s
Have a good day.
