Answer:
32.7 kilograms of aluminium oxide will be produced.
Explanation:
[tex]2 Al ( s ) + Fe_2O_3 ( s ) +heat\rightarrow Al_2O_3 ( s ) + 2 Fe ( l )[/tex]
Mass of aluminum = 17.3 kg = 17300 g (1 kg = 1000 g )
Moles of aluminium = [tex]\frac{17300 g}{27 g/mol}=640.74 mol[/tex]
According to reaction, 2 moles of aluminum gives 1 mole of aluminum oxide,then 640.74 moles of aluminum will give:
[tex]\frac{1}{2}\times 640.74 mol= 320.37 mol[/tex] of aluminum oxide
Mass of 320.37 moles of aluminum oxides:
320.37 mol × 102 g/mol = 32,677.74 g = 32.67774 kg ≈ 32.7 kg
32.7 kilograms of aluminium oxide will be produced.
