Answer:
45.7%
Explanation:
We first put down the balanced reaction equation. The actual yield of iron in moles is calculated from the given mass of iron and the relative atomic mass of iron. Since from the balanced reaction equation, 1 mole of iron III oxide yields 2 moles of iron, then twice the given amount of iron III oxide gives the theoretical yield in moles. From there, the percentage yield can be calculated as shown.
