Answer:
The approximate standard deviation of the sampling distribution of the mean is 0.078
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sample means with size n of at least 30 can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]
In this problem, we have that:
[tex]\sigma = 1.1, n = 200[/tex].
According to the central limit theorem, what is the approximate standard deviation of the sampling distribution of the mean?
[tex]s = \frac{1.1}{\sqrt{200}} = 0.078[/tex]
The approximate standard deviation of the sampling distribution of the mean is 0.078
