Answer:
Empirical formula is C₄H₈O
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number
Given data:
Mass of compound = 5.80 g
Mass of CO₂ = 14.2 g
Mass of water = 5.80 g
Empirical formula = ?
Solution:
Percentage of H = 5.80 / 5.80× 2/18 ×100= 11%
Percentage of C = 14.2 /5.8 ×12/44 × 100= 67%
Percentage of O = 100 -( 67+11) = 22%
Number of gram atoms:
Number of gram atoms of H = 11 / 1 = 11
Number of gram atoms of O = 22 / 16 = 1.4
Number of gram atoms of C = 67 / 12 = 5.6
Atomic ratio:
C : H : O
5.6/1.4 : 11/1.4 : 1.4/1.4
4 : 8 : 1
C : H : O = 4 : 8 : 1
Empirical formula is C₄H₈O.
