Answer:
5.36 grams the mass in grams of zinc nitrate the chemist has added to the flask.
Explanation:
[tex]Molarity=\frac{\text{Moles of solute}}{\text{Volume of the solution (L)}}[/tex]
Moles of zinc nitrate = n
Volume of the solution = 135.0 mL = 0.1350 L
Molarity of the solution = 0.21 M
[tex]0.21 M=\frac{n}{0.1350 L}[/tex]
[tex]n=0.21M\times 0.1350 L=0.02835 mol[/tex]
Mass of 0.02835 moles of zinc nitrate:
0.02835 mol × 189 g/mol = 5.358 g ≈ 5.36 g
5.36 grams the mass in grams of zinc nitrate the chemist has added to the flask.
