Respuesta :
Answer:
maximum amplitude = 0.08 m
Explanation:
Given that
Time period T= 0.58 s
acceleration of gravity g= 9.8 m/s²
We know that time period of simple harmonic motion given as
T = 2π/ω
0.58 = 2π/ω
ω = 10.83rad/s
ω=angular frequency
Lets take amplitude = A
The maximum acceleration given as
a= ω² A
The maximum acceleration should be equal to g ,then block does not separate
a= ω² A
9.8 = 10.83² A
A = 0.08m
maximum amplitude = 0.08 m
Given Information:
Period = T = 0.58 seconds
Acceleration due to gravity = g = 9.8 m/s²
Required Information:
Maximum amplitude = A = ?
Answer:
Maximum amplitude = 0.083 m
Explanation:
The relation between the period and angular velocity of a simple harmonic motion is given by
ω = 2π/T
Whereas the maximum acceleration is given by
a = ω²A
Where A is the corresponding maximum amplitude
a = (2π/T)²A
Now will we equate the maximum acceleration with acceleration due to gravity
g = (2π/T)²A
A = g/(2π/T)²
Finally, substitute the given values
A = 9.8/(2π/0.58)²
A = 9.8/117.35
A = 0.083 m
Therefore, the maximum amplitude for which the block doesn't separate from the plate is 0.083 m any increase beyond this value will result in separation.