Answer:
a. What are the minimum and maximum cycle times?
OT = 450 minutes
a. Minimum cycle time = length of longest task, which is 2.4 minutes.
Maximum cycle time = Σ task times = 18 minutes.
b. What range of output is theoretically possible for the line?
Range of output:
2.4 min: = [tex]\frac{450}{2.4} =[/tex] 187.5 units
18 min: = [tex]\frac{450}{18}[/tex] = 25 units
c. What is the minimum number of workstations needed if the maximum output rate is to be sought?
N = DxΣt / OT = 187.5(18) / 450 = 7.5, rounded off to 8.
d. What cycle time will provide an output rate of 125 units per day?
Output = OT/ CT,
Solving for CT, CT = 450 / 125 = 3.6 minutes per cycle
e. What output potential will result if the cycle time is (1) 9 minutes? (2) 15 minutes?
Potential output:
CT = 9 min: OT / CT = 450 / 9 = 50 units.
CT = 15 min: OT / CT = 450 / 15 = 30 units.
