Answer: 5.71kg and 10.33N
Explanation:
Recall,
Weight =mass × g
Where w = 56.0 N , g = 9.8 m/s2
56= m × 9.8
M = 56/9.8
M = 5.71 kg
At the surface of the moon, the mass still remains 5.71kg because it is a fundamental quantity it does not change irrespective of position.
Weight at the moon surface will change as a result of change in gravity. Hence, weight = mg
Where g=1.81m/s2, m= 5.71
W = 5.71×1.81
W = 10.33N
Question:
At the surface of Jupiter’s moon Io, the acceleration due to gravity is g=1.81 m/s². A watermelon weighs 56.0 N at the surface of the earth.
(a) What is the watermelon’s mass on the earth’s surface?
(b) What would be its mass and weight on the surface of Io?
Answer:
The answer to the question is
(a) 5.71 kg
(b) 10.34 N
Explanation:
The Weight of an object is given by
Weight = Mass × Acceleration due to gravity
on Earth the weight of the watermelon = 56 N
Therefore
The mass of the watermelon = [tex]\frac{Weight}{Acceleration.due . to . gravity}[/tex] = 56/9.8 = 5.71 kg
(b) On the surface of lo, the weight of the watermelon will be
Weight = Mass × Acceleration due to gravity
Where acceleration due to gravity on lo = 1.81 m/s²
Therefore the weight of the watermelon on lo = 1.81×5.7
= 10.34 N
