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If it takes 15 s for a certain sample of neon to effuse through a porous barrier, how much time will it take for the same amount of nitrogen gas to effuse through the barrier under the same conditions? 1. greater than 15 s 2. less than 15 s 3. 15 s

Respuesta :

Answer:

The correct answer is;

2. less than 15 s

Explanation:

Grahams law of effusion states

[tex]\frac{Rate 1}{Rate2} =\sqrt{\frac{Molar Mass2}{MolarMass 1} }[/tex]

Therefore

we have molar mass of neon gas = 20.18 g/mol

Molar mass of nitrogen gas = 28.014 g/mol

Which gives

[tex]\frac{Rate 1}{15} =\sqrt{\frac{20.18}{28.014} }[/tex] = 0.72

Therefore the rate of effusion of nitrogen gas is 0.72*15 = 12.73 s which is less than 15 s