Answer:
[tex]\dot W_{mean} = 5.094\, W[/tex]
Explanation:
The average power is ratio of change in kinetic energy to time required to accelerate. Changes in potential energy are neglected. That is:
[tex]\dot W_{mean} = \frac{\Delta K}{\Delta t}[/tex]
[tex]\dot W_{mean} = \frac{\frac{1}{2}\cdot m \cdot v_{f}^{2}}{\Delta t}[/tex]
[tex]\dot W_{mean} = \frac{\frac{1}{2}\cdot (0.57\,kg)\cdot (0.720\,\frac{m}{s} )^{2} }{29\times 10^{-3}\,s}[/tex]
[tex]\dot W_{mean} = 5.094\, W[/tex]
