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An electric motor rotating a workshop grinding wheel at 1.06 102 rev/min is switched off. Assume the wheel has a constant negative angular acceleration of magnitude 2.10 rad/s2. (a) How long does it take the grinding wheel to stop

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Answer:

t = 106π / 30*2.1

Explanation:

[tex]w_{i} = 1.06*10^{2}[/tex]    => 106

    => 106 x 2π/60

    => 106/30π

∝ = -2.1 rad/sec²

[tex]w_{f}[/tex] => 0

[tex]w_{f}[/tex] = [tex]w_{i}[/tex] + ∝t

∴ ([tex]w_{f}[/tex] - [tex]w_{i}[/tex]) / ∝ = t

t = 106π / 30*2.1

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